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5x^2-41x-765=0
a = 5; b = -41; c = -765;
Δ = b2-4ac
Δ = -412-4·5·(-765)
Δ = 16981
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-\sqrt{16981}}{2*5}=\frac{41-\sqrt{16981}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+\sqrt{16981}}{2*5}=\frac{41+\sqrt{16981}}{10} $
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